Question

помогите пж.............​

Answer 1

${x}^{3} - 2 {x}^{2} - 36x + 72 = 0 \\ ( {x}^{3} - 2 {x}^{2} ) + ( - 36x + 72) = 0 \\ {x}^{2} (x - 2) - 36(x - 2) = 0 \\ ( {x}^{2} - 36)(x -2 ) = 0 \\ (x - 6)(x + 6)(x - 2) = 0 \\ x _{1} = 6 \\ x_{2} = - 6 \\ x_{3} = 2$