Question

1) [2(x+y)-x=-6, 3x-(x - y) = 0; ​

Answer 1

Ответ:

$(2;-4)$

Объяснение:

$\left \{ {{2(x+y)-x=-6} \atop {3x-(x-y)=0}} \right. \\\\\left \{ {{2x+2y-x=-6} \atop {3x-x+y=0}} \right. \\\\\left \{ {{x+2y=-6} \atop {2x+y=0\ \ \ |\cdot(-2)}} \right. \\\\\left \{ {{x+2y=-6} \atop {-4x-2y=0}} \right.$

+______

$-3x=-6\ \ \ |:(-2)\\\\x=2$

$\left \{ {{x=2} \atop {2x+y=0}} \right. \\\\\left \{ {{x=2} \atop {2\cdot2+y=0}} \right. \\\\\left \{ {{x=2} \atop {4+y=0}} \right. \\\\\left \{ {{x=2} \atop {y=-4}} \right.$

Answer 2

Ответ:

(2; -4)

Объяснение:

{2(х + у) - х = -6

{3х - (х - у) = 0

{2х + 2у - х = -6

{3х - х + у = 0

{х + 2у = -6

{2х + у = 0

{х = -6 - 2у

{2х + у = 0

1)

2х + у = 0

2(-6 - 2у) + у = 0

-12 - 4у + у = 0

-4у + у = 0 + 12

-3у = 12

у = 12 : (-3)

у = -4

2)

х = -6 - 2у

х = -6 - 2 * (-4)

х = -6 + 8

х = 2