Question

Cпроcтіть вираз.
Дам 100б.

Answer 1

$\frac{3a}{a-4} - \frac{a+2}{5a-20}*\frac{240}{a^{2}+2a } = \frac{3a}{a-4} - \frac{a+2}{5(a-4)} * \frac{240}{a(a+2)} = \frac{3a}{a-4} - \frac{48}{a(a-4)} = \frac{3a^{2} - 48 }{a(a-4)} = \frac{3(a^{2}-16) }{a(a-4)} = \frac{3(a-4)(a+4) }{a(a-4)} = \frac{3(a+4)}{a}$