Question

Розв'язати 2 рівняння:
1) (х-1)²-25=0
2) 49-(2х+5)²=0

Answer 1

$\displaystyle\bf\\1)\\\\(x-1)^{2} -25=0\\\\(x-1)^{2} =25\\\\\\\left[\begin{array}{ccc}x-1=-5\\x-1=5\end{array}\right\\\\\\\left[\begin{array}{ccc}x_{1} =-4\\x_{2} =6\end{array}\right\\\\\\Otvet \ : \ -4 \ \ ; \ \ 6\\\\2)\\\\49-(2x+5)^{2} =0\\\\(2x+5)^{2} =49\\\\\\\left[\begin{array}{ccc}2x+5=-7\\2x+5=7\end{array}\right$

$\displaystyle\bf\\\left[\begin{array}{ccc}2x=-12\\2x=2\end{array}\right\\\\\\\left[\begin{array}{ccc}x_{1} =-6\\x_{2} =1\end{array}\right\\\\\\Otvet \ : \ -6 \ \ ; \ \ 1$