Question

ДАМ 65 БАЛЛОВ! СРОЧНО​

Answer 1

$\displaystyle\bf\\1)\\\\\frac{2(a+3)}{(a+3)(a-3)} =\frac{2}{a-3} \\\\2)\\\\\Big(\frac{5}{a-2} +\frac{3}{a+2} \Big)\cdot\frac{a^{2} -4}{8a+4} =\\\\\\=\frac{5\cdot(a+2)+3\cdot(a-2)}{(a-2)\cdot(a+2)}\cdot\frac{(a-2)\cdot(a+2)}{4\cdot(2a+1)} =\\\\\\=\frac{5a+10+3a-6}{4\cdot(2a+1)} =\frac{8a+4}{8a+4} =1$