Предмет: Математика, автор: nzrinhsnova683


0.8  |x + 6|  = 0.16  |x - 4|
..................​

Ответы

Автор ответа: Alexandr130398
0

Ответ:

-17/2; -13/3

Пошаговое объяснение:

0,8|x+6|=0.16|x-4|  |*25

20|x+6|=4|x-4|  |:4

5|x+6|=|x-4|  |^2

5²(x+6)²=(x-4)²

5²(x+6)²-(x-4)²=0

[5(x+6)-(x-4)][5(x+6)+(x-4)]=0

(5x+30-x+4)(5x+30+x-4)=0

(4x+34)(6x+26)=0

4x+34=0  или 6x+26=0

x=-34/4=-17/2  или  x=-26/6=-13/3

Автор ответа: 7x8
0

Ответ:

-8\frac{1}{2}

-4\frac{1}{3}

Пошаговое объяснение:

0,8 |x + 6| = 0,16 |x - 4|\ \ \ |:0,8

 |x + 6|= 0,2 |x - 4|

нули модулей

|x+6|=0\ \ \ \ \ \ \ \ \ \ |x-4|=0

x+6=0\ \ \ \ \ \ \ \ \ \ \ \ x-4=0

x=-6\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x=4

1.

x\in \left(-\infty;-6\right]

-(x + 6) =- 0,2 (x - 4)

-x - 6 =- 0,2x +0,8

-x + 0,2x=0,8+6

-0,8x=6,8\ \ \ |:(-0,8)

x=-\frac{68}{8}

x=-\frac{17}{2}

x=-8\frac{1}{2}

2.

x\in \left(-6;4\right]

x + 6 =- 0,2 (x - 4)

x +6 =- 0,2x +0,8

x + 0,2x=0,8-6

1,2x=-5,2\ \ \ |:1,2

x=-\frac{52}{12}

x=-\frac{13}{3}

x=-4\frac{1}{3}

3.

x\in \left(4;+\infty\right)

x + 6 = 0,2 (x - 4)

x +6 = 0,2x -0,8

x - 0,2x=-0,8-6

0,8x=-6,8\ \ \ |:0,8

x=-\frac{68}{8}

x=-\frac{17}{2}

x=-8\frac{1}{2}\not \in\left(4;+\infty\right)

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