Предмет: Математика, автор: Vitek123453

Вычислите площадь закрашенной фигуры.

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Автор ответа: NNNLLL54

0

Ответ:

Площадь закрашенной фигуры равна разности площади трапеции и площади ромба .

$\bf S=S_{trap.}-S_{romba}=\dfrac{36+20}{2}\cdot 25-\dfrac{1}{2}\cdot 25\cdot 18= 28\cdot 25-9\cdot 25=\\\\=(28-9)\cdot 25=19\cdot 25=475$

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