Предмет: Алгебра, автор: annazotkina61

ПОМОГИТЕ ПОЖАЛУЙСТА ОЧЕНЬ СРОЧНО УМОЛЯЮ ДАЮ 40 БАЛЛОВ С ОБЪЯСНЕНИЕМ ЖЕЛАТЕЛЬНО

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Ответы

Автор ответа: DiRaNs

1

Объяснение:

Будем действовать по формуле сокращенного умножения:

(a-b)*(a+b)=a²-b² - разность квадратов

а) (6-а)*(6+а)=6²-а²=36-а²

б) (11у-4)*(11у+4)=(11у)²-4²=121у²-16

в) (8х+7b)*(8x-7b)=(8х-7b)*(8x+7b)=(8x)²-(7b)²=64x²-49b²

г) (15с³-1)*(15с³+1)=(15с³)²-1²=225с⁶-1

Автор ответа: Universalka

0

$\displaystyle\bf\\1)\\\\(6-a)\cdot(6+a)=6^{2} -a^{2} =36-a^{2} \\\\2)\\\\(11y-4)\cdot(11y+4)=(11y)^{2} -4^{2} =121y^{2} -16\\\\3)\\\\(8x+7b)\cdot(8x-7b)=(8x)^{2} -(7b)^{2} =64x^{2} -49b^{2} \\\\4)\\\\(15c^{3} -1)\cdot(15c^{3} +1)=(15c^{3} )^{2} -1^{2} =225c^{6} -1$

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