Question

Решите уравнение: 2x-3/3-2-3x/2=4x+6/4

Answer 1

Ответ:

$x=3$

Объяснение:

$\frac{2x-3}{3}-\frac{2-3x}{2}=\frac{4x+6}{4}\\\frac{4(2x-3)-6(2-3x)}{12}=\frac{3(4x+6)}{12}\\4(2x-3)-6(2-3x)=3(4x+6)\\8x-12-12+18x=12x+18\\26x-24=12x+18\\26x-12x=18+24\\14x=42\\x=\frac{42}{14}\\x=3$

Answer 2

$\displaystyle\bf\\\frac{2x-3}{3} -\frac{2-3x}{2} =\frac{4x+6}{4} \\\\\\\frac{2x-3}{3} \cdot 12-\frac{2-3x}{2} \cdot 12=\frac{4x+6}{4} \cdot 12\\\\\\(2x-3)\cdot 4-(2-3x)\cdot 6=(4x+6)\cdot 3\\\\8x-12-12+18x=12x+18\\\\26x-24=12x+18\\\\26x-12x=18+24\\\\14x=42\\\\x=42:14\\\\\boxed{x=3}$