Question

Помогите пожалуйста!!!! Нужно с решением!!! Срочно!!!!!

Answer 1

Ответ:

Пошаговое объяснение:

а)

$\frac{1}{58}sin\frac{x}{58}\leq \frac{1}{116}\\sin\frac{x}{58}\leq \frac{1}{116}:\frac{1}{58} \\sin\frac{x}{58}\leq =0.5\\-\frac{7\pi }{6}+2\pi k \leq \frac{x}{58} \leq \frac{\pi }{6}+2\pi k$    k∈Z

=>  -7*58*π/6+116πk≤ x≤ 58π/6 +116 πk

=>  -203*π/3+116πk≤ x≤ 29π/3 +116 πk   ,k∈Z

б)

$\frac{1}{87}*cos(12x-\frac{\pi }{12}) \geq \frac{\sqrt{3} }{66}:\frac{1}{87} \\\frac{1}{87}*cos(12x-\frac{\pi }{12}) \geq \frac{\sqrt{3}*87 }{66}=\frac{\sqrt{3}*29 }{22}\\cos(12x-\frac{\pi }{12}) \geq \frac{\sqrt{3}*29 }{22}\\-arccos\frac{\sqrt{3}*29 }{22}+2\pi k\leq 12x-\pi /12\leq arccos\frac{\sqrt{3}*29 }{22}+2\pi k$  , k∈Z

=>( -arccos(29√3/22)+2πk-π/12)/12≤x≤ ( arccos(29√3/22)+2πk-π/12)/12

-arccos(29√3/22)/12+πk/6-π/144≤x≤ arccos(29√3/22)/12+πk/6-π/144 , k∈Z

c)3-22sin11x*cos11x<3

3-11sin 22x<3

11sin22x>0

sin22x>0

2πk<22x<π+2πk

πk/22<x<π/22 +πk/11       k∈Z