Предмет: Физика, автор: immmir737

Для данной электрической схемы R 5 Ом, R2=4 Ом, R = 3 Ом, R = 6 Ом. В.-2 Ом. Uab=36 В. Рассчитайте общее сопротивление цепи, силу тока и напряжение на каждом резисторе

Приложения:

Ответы

Автор ответа: zinovicgrigorij

Ответ:

Объяснение:

Дано:

R1=5 Ом

R2=4 Ом

R3=3 Ом

R4=6 Ом

R5=2 Ом

U=36В

----------------

R-?; U1-U5-?

I1-I5-?

R=(R1+R2+R3)*R4/(R1+R2+R3+R4)+R5=(5+4+3)*6/(5+4+3+6)+2=6 Ом

I=I5=U/R=36/6=6А

U5=I5*R5=6*2=12В

U4=U1+U2+U3=U-U5=36-12=24В

I4=U4/R4=24/6=4А

I1=I2=I3=I-I4=6-4=2А

U1=I1*R1=2*5=10В

U2=I2*R2=2*4=8В

U3=I3*R3=2*3=6В

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