Предмет: Математика, автор: heeeelllooooo

Найдите наименьшее значение суммы x+y+z,
где x, y, z-натуральные числа и 4у=7z, х=2z

Ответы

Автор ответа: seins88
2

Ответ:

=19

Пошаговое объяснение:

Min(x+y+z)= ?

4y=7z=> y=7z/4    ;   x=2z

2z+7z/4+z = 3z+7z/4

7z/4∈N => z(min)=4

=>Min(x+y+z)= 3*4+7*4/4 = 19

matilda17562: Впишите, пожалуйста, подробные пояснения.
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