Предмет: Геометрия, автор: mailpochta1012

ПОМОГИТЕ ПОЖАЛУЙСТА!!!!!

Приложения:

Ответы

Автор ответа: zmeura1204

Ответ:

V=256000sinDtgQ

Объяснение:

S(∆ACB)=½*AC*CB*sin∠ACB=

=½*80*80*sinD°=3200sinD°

tg∠LCB=LB/CB; →

LB=CB*tg∠LCB=80*tgQ°;

V=S(∆ACB)*LB=3200sinD°*80tgQ°=

=256000sinD°tgQ°

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