Question

Помогите с решением
2sinx=-√3

Answer 1

$\displaystyle\bf\\2Sinx=-\sqrt{3} \\\\Sinx=-\frac{\sqrt{3} }{2} \\\\\\x=(-1)^{k} arc Sin\Big(-\frac{\sqrt{3} }{2} \Big)+\pi k, \ k\in Z\\\\\\x=(-1)^{k} \Big(-\frac{\pi }{3} \Big)+\pi k, \ k\in Z\\\\\\x=(-1)^{k+1} \frac{\pi }{3} +\pi k, \ k\in Z$