Предмет: Физика, автор: yaroslav0379

Чому дорівнює абсолютне значення оптичної сили розсіювальної лінзи, фокусна відстань якої 20 см?
а) 0,2 дптр б) 20 дптр в) 5 дптр г) 0,05 дптр д) серед відповідей а-г немає правильної
задача

Ответы

Автор ответа: Alexander890

0

Ответ:

Переводим сантиметры в метры 20 см = 0,2м.

И по формуле считаем: Д= 1/F = 1/0,2 = 5 дптр

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