Question

Помогите пожалуйста ​

Answer 1

x=-3-y

(-3-y)^2-2y=14
9+4y+y^2=14
y=-5
y=1

x=-3-(-5)
x=2

x=-3-1
x=-4

Answer 2

$\displaystyle\bf\\\left \{ {{x + y = - 3} \atop { {x}^{2} - 2y = 14}} \right. \\ \displaystyle\bf\\\left \{ {{y = - 3 - x} \atop { {x}^{2} - 2( - 3 - x) = 14 }} \right. \\ \\ {x}^{2} + 2x + 6 - 14 = 0 \\ {x}^{2} + 2x - 8 = 0 \\ po \: \: \: teoreme \: \: \: vieta \\ {x}^{2} + bx + c = 0\\ x_{1} + x_{2} = - b\\ x_{1} x_{2} = c \\ x_{1}  +  x_{2} =  - 2\\ x_{1} x_{2} =  - 8\\ x_{1} = - 4  \\ x_{2} = 2 \\ \\ y_{1} = - 3 - ( - 4) = - 3 + 4 = 1 \\ y_{2} = - 3 - 2 = - 5$

Ответ: ( - 4 ; 1 ) и ( 2 ; - 5 )