Предмет: Химия, автор: a99942150

Допоможіть, будь ласка. Розставити коефіцієнти та визначити ОВР:
SO2+KON -> K2S+K2SO4+H2O

Ответы

Автор ответа: dyexfnf
1

Ответ:

Объяснение:

S²O₂ + KOH → K₂S⁻² + K₂S⁺⁶O₄ + H₂O

окисник      S⁺⁴ + 6е = S⁻²  процес відновлення

відновник  3S⁺⁴ - 6е = 3S⁺⁶  процес окислення

4SO₂ + 8KOH = K₂S + 3K₂SO₄ + 4H₂O

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