Question

 1) 3/2m+6-m-2/m^2+6m+9
 2) 5-a/a^2-8a+16+6/5a-20
 пожалуста решите очень надо прошу умоляю

Answer 1

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Answer 2

$frac{3}{2m+6}- frac{m-2}{m^2+6m+9}= frac{3}{2(m+3)}- frac{m-2}{(m+3)^2}= frac{3(m+3)-2(m-2)}{2(m+3)^2}=\\= frac{3m+9-2m+4}{2(m+3)^2} = frac{m+13}{2(m+3)^2} \\ frac{5-a}{a^2-8a+16}+ frac{6}{5a-20}= frac{5-a}{(a-4)^2}+ frac{6}{5(a-4)}= frac{5(5-a)+6(a-4)}{5(a-4)^2}= frac{25-5a+6a-24}{5(a-4)^2}=\\= frac{a+1}{5(a-4)^2}$