Question

Помогите решить задачу

Answer 1

$\displaystyle\bf\\(4y-3x)(4y+3x)=16y^{2}-9x^{2} \\\\(4y)^{2}-(3x)^{2} =16y^{2} -9x^{2} \\\\16y^{2} -9x^{2}=16y^{2} -9x^{2}\\\\Otvet \ : \ B) \ \boxed{4y}$