Предмет: Математика, автор: olesyabeglova003

28. Две прямые дороги образуют угол 40°. Автомобиль и велосипедист выезжают с перекрестка одновременно. Автомобиль едет по одной дороге со скоростью 10 м/с, велосипедист по другой со скоростью 5 м/с. Каково их расстояние по прямой через 20 с движения?
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mic61: S=(10+5)*sin(90-40/2)*20=300*sin70 метров

Ответы

Автор ответа: erik2512

Пошаговое объяснение:

10 м/с * 20 с = 200 м

5 м/с * 20 с = 100 м

c^2 = a^2 + b^2 - 2ab*cos(C)

c^2 = 200^2 + 100^2 - 2*200*100*cos(140°)

c^2 = 40000 + 10000 + 40000*cos(140°)

c^2 = 90000 + 40000*cos(140°)

c ≈ 273 м

Ответ:273 м

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