Question

умоляю, срочно надо

Answer 1

Объяснение:

$\displaystyle\\\frac{cos100^0}{cos50^0+sin50^0}-(cos^225^0-sin^225^0)=\frac{cos^250^0-sin^250^0}{cos50^0+sin50^0}-cos50^0=\\\\\\=\frac{(cos50^0-sin50^0)*(cos50^0+sin50^0)}{cos50^0+sin50^0} -cos50^0=\\\\=cos50^0-sin50^0-cos50^0=-sin50^0.$