Предмет: Физика, автор: 985468458inna

СРОЧНООООО.чому дорівнює енергія зарядженого конденсатора ємністю 10 мкф при напрузі на його обкладках 100В
ДАНО НУЖНО И РЕШЕНИЕ​

Ответы

Автор ответа: robotagadanilo
0

Дано:

Ємність (C) = 10 мкФ = 10 × 10⁻⁶ Ф (фарад)

Напруга (V) = 100 В (вольт)

Щоб визначити енергію (E) зарядженого конденсатора, можна використати формулу:

E = (1/2) * C * V^2

Підставляємо дані у формулу:

E = (1/2) * (10 × 10⁻⁶ Ф) * (100 В)^2

Обчислюємо:

E = (1/2) * (10 × 10⁻⁶) * (10000 В^2)

E = 5 × 10⁻² Дж

Отже, енергія зарядженого конденсатора ємністю 10 мкФ при напрузі 100 В дорівнює 5 × 10⁻² Дж


985468458inna: дано ради бога напишите
robotagadanilo: так я написав з самого початку
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