Question

решите уравнение (x+10)^2 = (2-x)^2

Answer 1

(x+10)²=(2-x)²
x²+20x+100=4-4x+x²
24x=-96
x=-96 :24
x=-4

Answer 2

$(x+10)^{2} = (2-x)^{2} \ \ x^{2} +20x+100=4-4x+ x^{2} \ \ 20x+4x= -100+4 \ \ 24x= -96 \ \ x=-4$