Question

решите неравенство дам 80 баллов ​

Answer 1

$\displaystyle\bf \frac{ {x}^{2}(1 - x) }{ {x}^{2} - 4x + 4 } \leqslant 0 \\ \frac{ {x}^{2}(x - 1) }{(x - 2) {}^{2} } \geqslant 0 \\ \\ \left \{ {{ {x}^{2}(x - 1)(x - 2) {}^{2} \geqslant 0} \atop {x\neq2 }} \right. \\ \\ - - - [0] - - - [1] + + + (2) + + + \\ x \: \epsilon\: \left\{0\right\}U[1; \: 2)U(2; \: + \propto)$