Question

f(x)=2x³+x²-2x f'(-1)​

Answer 1

$\displaystyle\bf\\f(x)=2x^{3} +x^{2} -2x\\\\\\f'(x)=2\cdot(x^{3})'+(x^{2} )'-2\cdot x'=2\cdot 3x^{2} +2x-2\cdot 1=6x^{2} -2x-2\\\\\\f'(-1)=6\cdot(-1)^{2} -2\cdot(-1)-2=6+2-2=6\\\\\\Otvet \ : \ f'(-1)=6$