Question

Помогите пж удущудзвзащащааддащ​

Answer 1

1.

$\displaystyle\bf\\\left \{ {{3(x - 1) - 2(1 + x) < 1} \atop {3x - 4 > 0 }} \right. \\ \\ 1) \: 3(x - 1) - 2(1 + x) < 1 \\ 3x - 3 - 2 - 2x < 1 \\ x < 1 + 5 \\ x < 6 \\ \\ 2) \: 3x - 4 > 0 \\ 3x > 4 \: \: | \div 3 \\ x > 1 \frac{1}{3} \\ \displaystyle\bf\\3) \: \left \{ {{x < 6} \atop {x > 1 \frac{1}{3} }} \right. \\ \\ x \: \epsilon \: (1 \frac{1}{3} ; \: 6)$

2.

$( \sqrt{6} + \sqrt{3} ) \sqrt{12} - 2 \sqrt{6} \times \sqrt{3} = \\ = \sqrt{6 \times 12} + \sqrt{3 \times 12} - 2 \sqrt{6 \times 3} = \\ = \sqrt{6 \times 6 \times 2} + \sqrt{3 \times 3 \times 4} - 2 \sqrt{2 \times 3 \times3 } = \\ = 6 \sqrt{2} + 3 \times 2 - 2 \times 3 \sqrt{2} = 6 \sqrt{2} + 6 - 6 \sqrt{2} = 6$