Question

Решить чистому ур-ий а) (23+3(x+y)=11 59-6х+7(x+Зу)=0​

Answer 1

{23 + 3 x + y = 11

{59-6x+7x+3y) = 0

{x=-4-y

{59-6x+7x+3y) = 0

59-6(-4-y) +7(-4-y+3y)=0

y=-11/14

x=-4-(-11/14)

x=-5/4

(x;y)=(-5/14; -11/14)