Предмет: Геометрия, автор: nazarenjagodonskii

площа трикутника =12 см знайти висоту трикутника яка проведена до сторони АС=8 см

Ответы

Автор ответа: Пеппер

1

Ответ:

10,5 см

Объяснение:

S=1/2 * a * h

42=1/2 * 8h

4h=42

h=10,5 см

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