Question

$left { {4^{x-1}leq16} atop {5^{2x+4}>25}} right.$

Answer 1

$4^{x-1} leq 16$
$4^{x-1} leq 4^2$
$x-1 leq 2$
$x leq 2+1$
$x leq 3$

$5^{2x+4}>25$
$5^{2x+4}>5^2$
$2x+4>2$
$x+2>1$
$x>1-2$
$x>-1$
$-1< x leq 3$
х є $(-1;3]$