Question

Знайдіть область визначення функції:
y=4/√5х-х^2+ √х
-4

Answer 1

$\displaystyle\bf\\y=\frac{4}{\sqrt{5x-x^{2} } } +\sqrt{x-4} \\\\\\\left \{ {{5x-x^{2} > 0} \atop {x-4\geq 0}} \right. \\\\\\\left \{ {{x^{2} -5x < 0} \atop {x\geq 4}} \right. \\\\\\\left \{ {{x\cdot(x-5) < 0} \atop {x\geq 4}} \right. \\\\\\\left \{ {{x\in(0 \ ; \ 5)} \atop {x\geq 4}} \right. \\\\\\Otvet \ : \ D(y)=\Big[4 \ ; \ 5\Big)$