Предмет: Математика, автор: emilbajmi

Из 300 учеников школы 95 играют только в крикет, 120 футбол, 80 — только в волейбол и 5 — не играют ни в какие игры. — Если наугад выбран один ученик, найти вероятность того, что a) он играет в волейбол b) он играет либо в крикет, либо в волейбол c) он не играет ни в футбол, ни в волейбол. [3]​

Ответы

Автор ответа: Аноним
0

Дано:

Общее количество учеников (N) = 300

Ученики, играющие только в крикет (C) = 95

Ученики, играющие только в футбол (F) = 120

Ученики, играющие только в волейбол (V) = 80

Ученики, не играющие вообще (N) = 5

a) Вероятность выбрать ученика, играющего в волейбол:

P(V) = V / N = 80 / 300 = 4 / 15

b) Вероятность выбрать ученика, играющего либо в крикет, либо в волейбол:

P(C или V) = (C + V) / N = (95 + 80) / 300 = 175 / 300 = 7 / 12

c) Вероятность выбрать ученика, не играющего ни в футбол, ни в волейбол:

P(не F и не V) = (N - (F + V)) / N = (5 - (120 + 80)) / 300 = -195 / 300 = -13 / 20

Oбратим внимание, что результат вероятности в пункте c) отрицательный. Это означает, что в условии задачи есть ошибка или противоречие. Вероятность не может быть отрицательной.

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