Question

Найдите производную функции y= 2+3xразделить 3-2x

Answer 1

$y = 2 + \frac{3x}{3 - 2x} \\ y' = \frac{(3x)'(3 - 2x) - (3 - 2x)' \times 3x}{(3 - 2x) {}^{2} } = \frac{3(3 - 2x )- 3x \times ( - 2)}{(3 - 2x) {}^{2} } = \\ = \frac{9 - 6x + 6x}{(3 - 2x {}^{2} } = \frac{9}{(3 - 2x) {}^{2} }$