Question

:{((х-1)(х-2)≥0@х(х-10)≤0)

Answer 1

$\displaystyle\bf\\\left \{ {{(x - 1)(x - 2) \geqslant 0} \atop {x(x - 10) \leqslant 0 }} \right. \\ \\ (x - 1)(x - 2) \geqslant 0 \\ + + + [1] - - - [2] + + + \\ x \: \epsilon \: ( - \propto; \: 1]U[2; \: + \propto) \\ \\ x(x - 10) \leqslant 0 \\ + + + [0] - - - [10] + + + \\ x \: \epsilon\: [0; \: 10 ] \\ \displaystyle\bf\\\left \{ {{x \: \epsilon \: ( - \propto; \: 1]U[2; \: + \propto)} \atop { x \: \epsilon\: [0; \: 10 ] }} \right. \\ \\ otvet \: \: \: x \: \epsilon\: [0; \: 1]U[2; \: 10]$