Question

Реши систему уравнений​

Answer 1

$\displaystyle\bf\\\left \{ {{(7 - x) {}^{2} - (8 +x) {}^{2} = 5y } \atop {11x + 4y - 14 = 0}} \right. \\ \displaystyle\bf\\\left \{ {{49 - 14x + {x}^{2} - 64 - 16x - {x}^{2} - 5y = 0 } \atop {11x + 4y = 14}} \right. \\ \displaystyle\bf\\\left \{ {{ - 30x - 5y = 15} \atop {11x + 4y = 14}} \right. \\ \displaystyle\bf\\\left \{ {{ - 6x - y = 3 \: \: | \times 4 } \atop {11x + 4y = 14}} \right. \\\displaystyle\bf\\ + \left \{ {{ - 24x - 4y = 12} \atop {11x + 4y = 14}} \right. \\ \\11x - 24x = 12 + 14 \\ - 13x = 26 \\ x = 26 \div ( - 13) \\ x = - 2 \\ \\ - 6 \times ( - 2) - y = 3 \\ 12 - y = 3 \\ y = 12 - 3 \\ y = 9$

Ответ: ( - 2 ; 9 )