Question

Розв'яжіть систему

{4(x-3)-5(y+1)=-6
{2(2x-1)+3(y-3)=8

Answer 1

$\displaystyle\bf\\\left \{ {{4(x-3)-5(y+1)=-6} \atop {2(2x-1)+3(y-3)=8}} \right. \\\\\\\left \{ {{4x-12-5y-5=-6} \atop {4x-2+3y-9=8}} \right. \\\\\\\left \{ {{4x-5y=-6+12+5} \atop {4x+3y=8+2+9}} \right.\\\\\\-\left \{ {{4x-5y=11} \atop {4x+3y=19}} \right. \\---------\\4x-5y-4x-3y=11-19\\\\-2y=-8\\\\y=4\\\\4x=19-3y=19-3\cdot 4=19-12=7\\\\x=7:4=1,75\\\\\\Otvet \ : \ (1,75 \ ; \ 4)$