Question

Разложить на множители:
121a²-81b²=
400n²-400mn+100m²=
-9y²+60y-100=
64+8x³=
512x³-343y⁶=​

Answer 1

Ответ:

Объяснение:

121a²-81b²=(11a)²-(9b)² = (11a-9b)(11a+9b).

400n²-400mn+100m²=(20n)²-2*20n*10m+(10m)² =

(20n-10m)²=(20n-10m)(20n-10m).

-9y²+60y-100=-((3y)²+2*3y*10+10²) = (3y+10)² =(3y+10)(3y+10).

64+8x³=4³+(2x)³ = (4+2x)(4²-8x+(2x)²) = (4+2x)(16-8x+4x²).

512x³-343y⁶=​(8x)³ - (7y²)³ = (8x-7y)(64x²+56xy²+49y⁴).