Question

помогите пж даю 30 баллов​

Answer 1

$\displaystyle\bf\\\left \{ {{ \frac{x + 2y}{6} - \frac{y - 3}{4} = 1 \: \: | \times 12 } \atop { \frac{x - 2}{4} - \frac{y - 4}{2} = 1 \: \: | \times 4}} \right. \\\displaystyle\bf\\\left \{ {{2(x + 2y) - 3(y - 3) = 12} \atop {x - 2 - 2(y - 4) = 4}} \right. \\\displaystyle\bf\\\left \{ {{2x + 4y - 3y + 9 = 12} \atop {x - 2 - 2y + 8 = 4}} \right. \\ \displaystyle\bf\\ \left \{ {{2x + y = 3 \: \: | \times 2} \atop {x -2 y = - 2}} \right. \\\displaystyle\bf\\ + \left \{ {{4x + 2y = 6} \atop {x - 2y = - 2}} \right. \\ \\ 4x + x = 6 - 2 \\ 5x = 4 \\ x = 4 \div 5 \\ x = 0.8 \\ \\ 2 \times 0.8 + y = 3 \\ 1.6 + y = 3 \\ y = 3 - 1.6 \\ y = 1.4$

Ответ: ( 0,8 ; 1,4 )