Question

Знайдіть 2.2. Розв’яжіть рівняння x3 - 4x² - 4x+16=0.​

Answer 1

$\displaystyle\bf\\x^{3} -4x^{2} -4x+16=0\\\\(x^{3} -4x^{2}) -(4x-16)=0\\\\x^{2} \cdot(x-4)-4\cdot(x-4)=0\\\\(x-4)\cdot(x^{2} -4)=0\\\\(x-4)\cdot(x-2)\cdot(x+2)=0\\\\\\\left[\begin{array}{ccc}x-4=0\\x-2=0\\x+2=0\end{array}\right\\\\\\\left[\begin{array}{ccc}x_{1} =4\\x_{2} =2\\x_{3}=-2 \end{array}\right\\\\\\Otvet \ : \ 4 \ ; \ 2 \ ; \ -2$