Question

РІВНЯННЯ!!!! ДАЮ 60
(х-5)(х+5)-х(5+х)=0

Answer 1

$\displaystyle\bf\\(x-5)(x+5)-x(5+x)=0\\\\x^{2} -5^{2} -x\cdot 5-x\cdot x=0\\\\x^{2} -25-5x-x^{2} =0\\\\-5x=25\\\\x=25:(-5)\\\\\boxed{x=-5}$

Answer 2

$(x -5 )(x + 5) - x(5 + x) = 0 \\ (x + 5)(x - 5 - x) = 0 \\ (x + 5) \times ( - 5) = 0 \\ x + 5 = 0 \\ x = - 5$