Предмет: Физика, автор: tanya874p6o7i2

Допоможіть будь ласка

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Автор ответа: lvv9136

0

Ответ:

Объяснение:

№3 T =247 °C = 520 К;

p = 0,42 МПа = 4,2* 10⁵ Па;

М= 2 * 10⁻³ кг/моль;

p(плотность) - ? Из уравнения Менделеева Клапейрона: pV = vRT

v = m/M; V = m/ρ Подставляем: pm/p = m/MRT; ρ = pM/RT;

p = 4,2 * 10⁵ * 2 * 10⁻³/(8,31 * 520) = 0,194 кг/м³

№4 Т=240 °С=513 К;

М= 2 * 10⁻³ кг/моль;

υсер ? m₀*υ²/2=3/2*kT; m₀=M/Na=2*10⁻³/(6*10²³)=0,33*10⁻²⁶ kг;

υ=√(3*kT/m₀)=√(3*1,38*10⁻²³*513/(0,33*10⁻²⁶))=2537 м/c;

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