Предмет: Математика, автор: fanna6495

У прямокутному трикутнику ABC, кут С-90. ВС-18 см, AB-23 см. Знайдіть sinB, cosB, tgB.
30 балів!!!​

Ответы

Автор ответа: dudkovaleriia
0

Ответ:

Пошаговое объяснение:

Застосуємо теорему Піфагора для знаходження довжини гіпотенузи:AC = sqrt(AB^2 + BC^2)Але оскільки С - прямий кут і BC - катет, тоAC = BC / cos(B)Таким чином,BC / cos(B) = sqrt(AB^2 + BC^2)BC^2 / cos^2(B) = AB^2 + BC^2BC^2 * sin^2(B) = AB^2sin(B) = AB / BC = 23 / 18cos(B) = BC / AC = BC / (BC / cos(B)) = cos(B)Отже, cos(B) = sqrt(1 - sin^2(B)) = sqrt(1 - (23/18)^2) ≈ 0.684tg(B) = sin(B) / cos(B) = (23/18) / 0.684 ≈ 1.446Отримали:sin(B) ≈ 0.777cos(B) ≈ 0.684tg(B) ≈ 1.446

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