Question

2) 1 x-2 x 2 + > 3 x-1 ;

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Answer 1

(x+1)(x+2)+(x−2)(x−1)=3(x−1)(x+2)
x
2
+3x+2+x
2
−3x+2=3[x
2
+x−2]
2x
2
+4=3x
2
+3x−6
x
2
+3x−10=0
(x+5)(x−2)=0
[x=2,−5]