Question

найдите значение многочлена х^2-4х+1 при х=1/4; -3; 2-√3

Answer 1

$\displaystyle\bf\\x^{2} -4x+1\\\\1) \ x=\frac{1}{4} \\\\\\\Big(\frac{1}{4} \Big)^{2} -4\cdot \frac{1}{4} +1=\frac{1}{16} -1+1=\frac{1}{16} \\\\\\2)\ x=-3\\\\(-3)^{2} -4\cdot(-3)+1=9+12+1=22\\\\\\3) \ x=2-\sqrt{3} \\\\(2-\sqrt{3})^{2} -4\cdot(2-\sqrt{3} )+1=4-4\sqrt{3} +3-8+4\sqrt{3} +1=0$