Question

Дана функция y(x)=-3x^2-4x+5. Найдите y(3-x)

Answer 1

y(3-x)=-3(3-x)^2-4(3-x)+5=-3(9-6x+x^2)-12+4x=-27+18x-3x^2-12+4x=-3x^2+22x-39,

y(3-x)=-3x^2+22x-39.