Question

1 Розв'яжiть рiвняння .Сррчно​

Answer 1

$\displaystyle\bf\\\boxed{x^{2} =|x|^{2} }\\\\\\3x^{2} +\frac{x^{2} }{|x|} -4=0\\\\\\3\cdot|x|^{2} +\frac{|x|^{2} }{|x|} -4=0\\\\\\3\cdot|x|^{2} +|x|-4=0 \ \ , \ \ x\neq 0\\\\\\|x|=m \ , \ m > 0\ \ \Rightarrow \ \ 3m^{2} +m-4=0\\\\D=1^{2} -4\cdot 3\cdot(-4)=1+48=49=7^{2} \\\\\\m_{1} =\frac{-1+7}{6} =1\\\\m_{2} =\frac{-1-7}{6}=-1\frac{1}{3} < 0 \ - \ neyd\\\\\\|x|=1\\\\x_{1} =-1 \ \ ; \ \ x_{2} =1\\\\Otvet \ : \ -1 \ ; \ 1$