Question

даю максимально балов​

Answer 1

Сначала разложим на множители числитель :

$\displaystyle\bf\\2x^{2} +x-6=0\\\\D=1^{2} -4\cdot 2\cdot(-6)=1+48=49=7^{2} \\\\\\x_{1} =\frac{-1-7}{4} =\frac{-8}{4} =-2\\\\\\x_{2} =\frac{-1+7}{4} =\frac{6}{4} =1,5\\\\\\\boxed{2x^{2} +x-6=2\cdot(x+2)\cdot(x-1,5)}\\\\\\\frac{2x^{2} +x-6}{4x-8} =\frac{2(x+2)(x-1,5)}{4(x-2)} =\\\\\\=\frac{(x+2)(x-1,5)}{2x-4}$