Предмет: Физика, автор: polinabagnuk280

жорсткість пружини дорівнює 100Н/м. Яка сила пружності при видовженні її на 5 см?

Ответы

Автор ответа: agrabar6
1
Дано:
k=100Н/м
x=0,05м
F-?
——————
F=kx=100*0,05=5H
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