Question

7(х-4)=5 (х+4)
3(у+1)=6 (1-у)+6
2(х-3)-3(4-х)=5
7+4(3-у)=5(у+2)
12-5(х+1)=7+3х-2х​

Answer 1

Ответ:

1) 7(x-4)=5(x+4)

7x-28=5x+20

7x-5x=20+28

2x=48

x=48÷2

x=24

2) 3(y+1)=6(1-y)+6

3y+3=6-6y+6

3y+6y=6+6-3

9y=9

y=9÷9

y=1

3) 2(x-3)-3(4-x)=5

2x-6-12+3x=5

2x+3x=5+6+12

5x=23

x=23÷5

x=4,6

4) 7+4(3-y)=5(y+2)

7+12-4y=5y+10

-4y-5y=10-7-12

-9y=-9

y=-9÷(-9)

y=1

5) 12-5(x+1)=7+3x-2x

12-5x-5=7+3x-2x

-5x-3x+2x=7-12+5

-6x=0

x=0÷(-6)

x=0