Question

помогите пожалуйста 50б дам срочно !​

Answer 1

Объяснение:

$\displaystyle\\\left \{ {{52-2x-x^2 < 4} \atop {7x-4 < 38}} \right. \ \ \ \ \left \{ {{x^2+2x-48 > 0} \atop {7x < 42\ |:7}} \right. \ \ \ \ \left \{ {{x^2+8x-6x-48 > 0} \atop {x < 6}} \right. \\\\\\\left \{ {{x*(x+8)-6*(x+8) > 0} \atop {x < 6}} \right. \ \ \ \ \ \ \left \{ {{(x+8)*(x-6) > 0} \atop {x < 6}} \right. \\\\(x+8)*(x-6) > 0$

-∞__+__-8__-__6__+__+∞               ⇒

x∈(-∞;-8)U(6;+∞).         ⇒

$\displaystyle\\\left \{ {{x\in(-\infty;-8)U(6;+\infty)} \atop {x\in(-\infty;6)}} \right. \ \ \ \ \ \ \Rightarrow\\\\x\in(-\infty;-8).$

Ответ: x∈(-∞;-8).