Question

[(3 целых 8/9*2,4+0,6*3 целых 8/9)*1 целая 6/7:2,6+0,4*(2 целых 3/28-1 целая 4/21)]:0,1. знаменатель (3,125+1 целая 9/40)*4
ПОМОГИТЕ ПОЖАЛУЙСТА ОЧЕНЬ СРОЧНО (ПО ДЕЙСТВИЯМ)​

Answer 1

$1) \: 3 \frac{8}{9} \times 2.4 + 0.6 \times 3 \frac{8}{9} = 3 \frac{8}{9} \times (2.4 + 0.6) = \frac{35}{9} \times 3 = \frac{35}{3} \\ 2) \: \frac{35}{3} \times 1 \frac{6}{7} \div 2.6 = \frac{35 \times 13 \times 5}{3 \times 7 \times 13} = \frac{5 \times 5}{3} = \frac{25}{3} = 8 \frac{1}{3} \\ 3) \: 2 \frac{3}{28} - 1 \frac{4}{21} = 2 \frac{9}{84} - 1 \frac{16}{84} = 1 \frac{93}{81} - 1 \frac{16}{84} = \frac{77}{84} = \frac{11}{12} \\ 4) \: 0.4 \times \frac{11}{12} = \frac{2 \times 11}{5 \times 12} = \frac{11}{5 \times 6} = \frac{11}{30} \\ 5) \: 8 \frac{1}{3} + \frac{11}{30} = 8 \frac{10}{30} + \frac{11}{30} = 8 \frac{21}{30} = 8 \frac{7}{10} = 8.7 \\ 6) \: 8.7 \div 0.1 = 87 \\ 7) \: 3.125 + 1 \frac{9}{40} = 3 \frac{1}{8} + 1 \frac{9}{40} = 3 \frac{5}{40} + 1 \frac{9}{40} = 4 \frac{14}{40} = 4 \frac{7}{20} \\ 8)4 \frac{7}{20} \times 4 = \frac{87 \times 4}{20} = \frac{87}{5} = 17.4 \\ 9) \: 87 \div 17.4 = 5$

Ответ: 5